Sample Code for adding a button for SubGrid and passing id of the selected records (CRM 2011)

Simply replace the entity schema name with your entity

  <RibbonDiffXml>
        <CustomActions>
          <CustomAction Id="MyOrg.CustomAction" Location="Mscrm.SubGrid.entitySchemaName.MainTab.Management.Controls._children" Sequence="50">
            <CommandUIDefinition>
              <Button Id="MyOrg.Button" ToolTipTitle="Upload Required Document" ToolTipDescription="Upload Required Documents for the Case" Command="MyOrg.Command" Sequence="50" LabelText="Upload Document" Alt="Upload Document To Portal" Image16by16="/_imgs/ribbon/AddEmail_16.png" Image32by32="/_imgs/ribbon/Email_32.png" TemplateAlias="o1" />
            </CommandUIDefinition>
          </CustomAction>
        </CustomActions>
        <Templates>
          <RibbonTemplates Id="Mscrm.Templates"></RibbonTemplates>
        </Templates>
        <CommandDefinitions>
          <CommandDefinition Id="MyOrg.Command">
            <EnableRules />
            <DisplayRules />
            <Actions>
              <JavaScriptFunction Library="$webresource:new_test" FunctionName="showvalue">
                <StringParameter Value="Guid(s) Selected" > </StringParameter>
                <CrmParameter Value="SelectedControlSelectedItemIds"></CrmParameter>
              </JavaScriptFunction>
            </Actions>
          </CommandDefinition>
        </CommandDefinitions>
        <RuleDefinitions>
          <TabDisplayRules>
          </TabDisplayRules>
          <DisplayRules />
          <EnableRules />
        </RuleDefinitions>
        <LocLabels />
      </RibbonDiffXml>

Function for the jscript web resource.

function showvalue(){

alert(value);

}

Hope it helps.

Author: Nishant Rana

I love working in and sharing everything about Microsoft.NET technology ! View all posts by Nishant Rana