Serialize and Deserialize InfoPath form and extract the attachment using WebClient in C#

Hi,

Suppose this is our InfoPath form

First we will generate the class for the above InfoPath form

https://nishantrana.me/2014/07/13/generate-a-c-class-from-an-infopath-form/

The sample code

myFields invoice = null;
WebClient webclient = new WebClient();
webclient.UseDefaultCredentials = true;

using (Stream fileStream = webclient.OpenRead("http://server:5000/formlibrary/FirstForm.xml?NoRedirect=true"))
{
if (fileStream != null)
{
XmlTextReader reader = new XmlTextReader(fileStream);

reader.Read();
reader.MoveToContent();

XmlSerializer xser = new XmlSerializer(typeof(myFields));
myFields invoiceInfopath = (myFields)xser.Deserialize(reader);
byte[] b = invoiceInfopath.field2;

// filename
int nameBufferLen = b[20] * 2;
byte[] fileNameBufffer = new Byte[nameBufferLen];

for (int i = 0; i < nameBufferLen; i++)
{
fileNameBufffer[i] = b[24 + i];
}

char[] charFileName = UnicodeEncoding.Unicode.GetChars(fileNameBufffer);
string fileName = new string(charFileName);
fileName = fileName.Substring(0, fileName.Length - 1);

// attchment
byte[] fileContent = new byte[b.Length - (24 + nameBufferLen)];

for (int i = 0; i < fileContent.Length; i++)
{
fileContent[i] = b[24 + nameBufferLen + i];
}

FileStream fs = new FileStream(@"C:\test\" + fileName, FileMode.Create);
fs.Write(fileContent, 0, fileContent.Length);
fs.Close();
}

Hope it helps.

Author: Nishant Rana

I love working in and sharing everything about Microsoft.NET technology ! View all posts by Nishant Rana