Tag: C#

How to – Split List into equal parts in C#


Hi,

Had a requirement to split a List in 3 smaller lists.

For e.g. if a list has 13 different elements.

It has to split into 3 list containing 5, 5 and 3 elements in it.

The helpful post

http://stackoverflow.com/questions/3892734/split-c-sharp-collection-into-equal-parts-maintaining-sort

Hope it helps !

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How to – Remove duplicate objects in list in C#


Just sharing a sample code to remove duplicates from a list using LINQ

public class MyClass
{
public string ID { get; set; }
public string Value { get; set; }

}

List<MyClass> myList = new List<MyClass>();
var xrmOptionSet = new MyClass();
xrmOptionSet.ID = "1";
xrmOptionSet.Value = "100";
var xrmOptionSet1 = new MyClass();
xrmOptionSet1.ID = "2";
xrmOptionSet1.Value = "200";
var xrmOptionSet2 = new MyClass();
xrmOptionSet2.ID = "1";
xrmOptionSet2.Value = "100";
myList.Add(xrmOptionSet);
myList.Add(xrmOptionSet1);
myList.Add(xrmOptionSet2);

// here we are first grouping the result by label and then picking the first item from each group
var myDistinctList = myList.GroupBy(i => i.ID)
.Select(g => g.First()).ToList();

Hope it helps..

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Serialize and Deserialize InfoPath form and extract the attachment using WebClient in C#


Hi,

Suppose this is our InfoPath form

First we will generate the class for the above InfoPath form

https://nishantrana.me/2014/07/13/generate-a-c-class-from-an-infopath-form/

The sample code


myFields invoice = null;
WebClient webclient = new WebClient();
webclient.UseDefaultCredentials = true;

using (Stream fileStream = webclient.OpenRead("http://server:5000/formlibrary/FirstForm.xml?NoRedirect=true"))
{
if (fileStream != null)
{
XmlTextReader reader = new XmlTextReader(fileStream);

reader.Read();
reader.MoveToContent();

XmlSerializer xser = new XmlSerializer(typeof(myFields));
myFields invoiceInfopath = (myFields)xser.Deserialize(reader);
byte[] b = invoiceInfopath.field2;

// filename
int nameBufferLen = b[20] * 2;
byte[] fileNameBufffer = new Byte[nameBufferLen];

for (int i = 0; i < nameBufferLen; i++)
{
fileNameBufffer[i] = b[24 + i];
}

char[] charFileName = UnicodeEncoding.Unicode.GetChars(fileNameBufffer);
string fileName = new string(charFileName);
fileName = fileName.Substring(0, fileName.Length - 1);

// attchment
byte[] fileContent = new byte[b.Length - (24 + nameBufferLen)];

for (int i = 0; i < fileContent.Length; i++)
{
fileContent[i] = b[24 + nameBufferLen + i];
}

FileStream fs = new FileStream(@"C:\test\" + fileName, FileMode.Create);
fs.Write(fileContent, 0, fileContent.Length);
fs.Close();
}

Hope it helps.

How to Read the InfoPath content and extract the attachment using XMLDocument in C#


The InfoPath form:-

The namespace and the field1 that is node that contains the attachment

Sample Code:


XmlDocument myDoc = new XmlDocument();
myDoc.Load(@"C:\test\form.xml");

// specify the name space
XmlNamespaceManager ns = new XmlNamespaceManager(myDoc.NameTable);
ns.AddNamespace("my", "http://schemas.microsoft.com/office/infopath/2003/myXSD/2014-07-12T15:29:09");

// the node that contains the attachment
XmlNodeList nl = myDoc.SelectNodes("/my:myFields/my:group1/my:group2/my:field1", ns);
foreach (XmlNode n in nl)
{
string s = n.InnerText;
byte[] b = Convert.FromBase64String(s);
int nameBufferLen = b[20] * 2;

// file name buffer to get the filename with extension
byte[] fileNameBufffer = new Byte[nameBufferLen];

for (int i = 0; i < nameBufferLen; i++)
{
fileNameBufffer[i] = b[24 + i];
}
char[] charFileName = UnicodeEncoding.Unicode.GetChars(fileNameBufffer);
string fileName = new string(charFileName);
fileName = fileName.Substring(0, fileName.Length - 1);

// byte array for the remaining content
byte[] fileContent = new byte[b.Length - (24 + nameBufferLen)];

for (int i = 0; i < fileContent.Length; i++)
{
fileContent[i] = b[24 + nameBufferLen + i];
}

FileStream fs = new FileStream(@"C:\test\" + fileName, FileMode.Create);
fs.Write(fileContent, 0, fileContent.Length);
fs.Close();

}

Hope it helps..

 

 

 

 

Generate a C# class from an InfoPath form


To generate a C# class from change the extension to .cab from .xsn.

Open and copy the content of cab file to a separate folder

Open the Visual Studio Developer Command Prompt and run the XSD.exe to generate the class

 

Hope it helps…

Converting XML to C# Literal


At times we need to convert the XML string to Literal. And it is not fun. While searching for online tool that could help, I found this XML Formatter tool

http://xmltoolbox.appspot.com/

Hope it helps.